{"id":5725,"date":"2019-05-08T14:03:16","date_gmt":"2019-05-08T14:03:16","guid":{"rendered":"http:\/\/javan.courses\/?page_id=5725"},"modified":"2021-02-09T14:29:48","modified_gmt":"2021-02-09T14:29:48","slug":"series-1-impedance-conversion-theories-and-techniques","status":"publish","type":"page","link":"https:\/\/javan.courses\/?page_id=5725","title":{"rendered":"SERIES 1- IMPEDANCE CONVERSION THEORIES AND TECHNIQUES"},"content":{"rendered":"<p><strong>1. General Concept<\/strong><\/p>\n<p>1.1<strong>. Case 1.<\/strong> Low Frequency Analysis<\/p>\n<p>1.1.1. Mathematical Method<\/p>\n<p>1.1.2. Graphical Method<\/p>\n<p>1.2<strong>. Case 2.<\/strong> High Frequency Signals<\/p>\n<p><strong>2. Methodologies<\/strong><\/p>\n<p><strong>2.1. Transformer Method<\/strong><\/p>\n<p><strong>2.2. Transmission Line Technology<\/strong><\/p>\n<p>2.2.1. Short Circuited T-line<\/p>\n<p>2.2.2. Open Circuited T-line<\/p>\n<p>2.2.3. Quarter-wave Transformer<\/p>\n<p>2.2.4. Pure Input Resistance<\/p>\n<p>2.2.5. Stub Matching<\/p>\n<p><strong>2.3. Solid State Electronics \u2013 Impedance Conversion<\/strong><\/p>\n<p><strong>2.4. Antenna Impedance Matching<\/strong><\/p>\n<p>2.4.1. Half-Wave Dipole<\/p>\n<p>2.4.2. Folded \u2013 Dipole<\/p>\n<p>2.4.3. Quarter-Wave Mono-Pole<\/p>\n<p>2.4.4. Balun<\/p>\n<p><strong>2.5. Microwave Antennas<\/strong><\/p>\n<p><strong>2.6. Optical Lenses<\/strong><\/p>\n<p><strong>2.7 Acoustical Instruments<\/strong><\/p>\n<p><strong>Appendices<\/strong><\/p>\n<p><strong>1. Communication Cables Losses Per 100 Ft.<\/strong><\/p>\n<p><strong>2. Lossless Transmission Lines Characteristics<\/strong><\/p>\n<p><strong>References<\/strong><\/p>\n<p><strong>Problems<\/strong><\/p>\n<p><strong>1. General Concept<\/strong><\/p>\n<p>Electronic signals, in contrast to power line, are made of complex wave forms mixed with different frequencies and noise low in amplitude especially in industrial applications such as sensors outputs. This requires complicated signal processing, filtering, and amplification. Table 1 shows the approximate values of some common electronics signals.<\/p>\n<p style=\"text-align: center;\"><strong>Table 1- Approximate values of some common electronic signals<\/strong><\/p>\n<table>\n<tbody>\n<tr>\n<td>Frequency (Hz)<\/td>\n<td>Level<\/td>\n<td>Signal<\/td>\n<\/tr>\n<tr>\n<td>100-20 k<\/td>\n<td>1-100 \u03bcV<\/td>\n<td>Microphone<\/td>\n<\/tr>\n<tr>\n<td>500 kHz-30 MHz88-108 MHz<\/td>\n<td>mV\/\u03bcV<\/td>\n<td>Radio waves,A.M\/F.M<\/td>\n<\/tr>\n<tr>\n<td>2.45 GHz<\/td>\n<td>mV<\/td>\n<td>Bluetooth\/Wi-Fi<\/td>\n<\/tr>\n<tr>\n<td>821-941 MHz<\/td>\n<td>50\u03bcW\/m<sup>2<\/sup><\/td>\n<td>Cell phones<\/td>\n<\/tr>\n<tr>\n<td>1.575 GHz<\/td>\n<td>\u03bcV<\/td>\n<td>GPS<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>It is clear from this table that to obtain a fait full reproduction of the transmitted information, receiver will have complex tasks of; converting the frequency, filtering the noise, and amplifying the signal. This series will only discuss signal amplification by means of impedance matching techniques. Frequency conversion and filtering are covered in almost all communication textbooks.<\/p>\n<p>Consider a simple circuit shown in Fig.1.<\/p>\n<p><img loading=\"lazy\" width=\"286\" height=\"102\" class=\"wp-image-5726 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-374.png\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig.1 A simple electronic circuit<\/strong><\/p>\n<p>The signal generator V<sub>s<\/sub>, can be considered as a received signal from the antenna, as audio signal from the headphone, or outputs from any kind of industrial sensors. The question is: under what conditions, load can receive maximum power. In other word what must be the value of the load to optimize receiver power. The answer has been provided in almost all texts books, first course in electrical engineering. Basically, it requires the determination of power in the load and maximizing it with respect to the variable, which in our case is the magnitude of the load resistance or its reactance. We outline the procedure below for two cases;<\/p>\n<p>1.1.<strong> Case 1- <\/strong>Low Frequency Analysis: under this assumption, signal source can be considered resistive. Frequency should not overlap H.F. region. Referring to Fig.1, power in the load is calculated as follows;<\/p>\n<p><img loading=\"lazy\" width=\"267\" height=\"49\" class=\"wp-image-5727\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/p_li2r_l-left-fracv_sr_sr_l-33.gif\" alt=\"P_{L}=I^{2}R_{L}=\\left ( \\frac{V_{s}}{R_{s}+R_{L}}\\right )^{2}R_{L}\\, \\, (1)\" \/><\/p>\n<p>There are two general methods to find the optimum value of R<sub>L<\/sub>, which yields maximum power; mathematical or graphical.<\/p>\n<p>1.1.1. Mathematical Method:<\/p>\n<p><img loading=\"lazy\" width=\"384\" height=\"45\" class=\"wp-image-5728\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-jpeg15-gif-31.gif\" alt=\"C:\\Users\\hank\\Desktop\\jpeg15.gif\" \/><\/p>\n<p><img loading=\"lazy\" width=\"105\" height=\"18\" class=\"wp-image-5729\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/r_lr_s-3-31.gif\" alt=\"R_{L}=R_{s}\\, \\, \\, \\, \\, (3)\" \/><\/p>\n<p>Under this equal termination, the load voltage will be V<sub>s<\/sub>\/2 and the maximum load power will be;<\/p>\n<p><img loading=\"lazy\" width=\"248\" height=\"21\" class=\"wp-image-5730\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/p_lmax-v_s-22-r_l-1-33.gif\" alt=\"P_{L}(max)= (V_{s}\/2)^{2}\/R_{L}\\: \\: \\: \\: \\: \\: \\: \\, \\, \\, \\, \\, (4)\" \/><\/p>\n<p>With Rs being equal RL, source resistance voltage will also be equal to (Vs\/2), and thus its power will be equal to load power. Equation (3) establishes an important electronic property for optimal signal reception. Please refer to problem section for some interesting related questions.<\/p>\n<p>1.1.2. Graphical Method: We have plotted P<sub>L<\/sub> vs R<sub>L<\/sub> for V<sub>s<\/sub>=1V and Rs =50\u03a9 and Rs=100\u03a9 with the result shown in Fig 2 for the data file given in table 2. Again, it is clear from this figure that maximum power is obtained for R<sub>L<\/sub> =Rs.<\/p>\n<p style=\"text-align: center;\"><strong>Table 2 \u2013 Data file for equation (4)<\/strong><\/p>\n<p style=\"text-align: center;\">&gt;&gt; RL=0:1:400;<\/p>\n<p style=\"text-align: center;\">&gt;&gt; Vs=5;<\/p>\n<p style=\"text-align: center;\">&gt;&gt; Rs1=50;<\/p>\n<p style=\"text-align: center;\">&gt;&gt; Rs2=100;<\/p>\n<p style=\"text-align: center;\">&gt;&gt; y1=((Vs.\/(Rs1+RL)).^2).*RL;<\/p>\n<p style=\"text-align: center;\">&gt;&gt; y2=((Vs.\/(Rs2+RL)).^2).*RL;<\/p>\n<p style=\"text-align: center;\">&gt; plot (RL,y1,RL,y2)<\/p>\n<p style=\"text-align: center;\"><img loading=\"lazy\" width=\"267\" height=\"139\" class=\"wp-image-5731\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-375.png\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 2 Graphical method of obtaining optimum load resistance<\/strong><\/p>\n<p style=\"text-align: left;\">1.2.<strong> Case 2 <\/strong>\u2013 Higher Frequency Signals: AT H.F. (100 MHz and above) source becomes reactive due to wires leads. For example, a 50\u03a9 source having 1\u03bcH of inductance, at 100 MHz will have an inductive reactance of<\/p>\n<p>|X<sub>s<\/sub>| = 2\u03c0f (1 x 10<sup>-6<\/sup>) \u0334\u2245628\u03a9!\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(5)<\/p>\n<p>In addition, the source impedance will be:<\/p>\n<p>Z<sub>s<\/sub> = 50 + j 628\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(6)<\/p>\n<p>Thus, R<sub>L<\/sub> and R<sub>s <\/sub>of Fig. 1 should be replaced by Z<sub>L<\/sub> and Z<sub>s<\/sub> as shown in Fig. 3.<\/p>\n<p><img loading=\"lazy\" width=\"301\" height=\"102\" class=\"wp-image-5732 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-376.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-376.png 301w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-376-300x102.png 300w\" sizes=\"(max-width: 301px) 100vw, 301px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 3 A simple reactive loads and source circuit<\/strong><\/p>\n<p>Under such condition load must have a susceptance part to cancel the reactance part of the source, in addition to R<sub>L<\/sub> = R<sub>s<\/sub>. Following the same procedure for resistive source it can be shown that in this case, to obtain maximum power in the load, we must have<\/p>\n<p>Z<sub>L<\/sub> = Zs*\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (7)<\/p>\n<p>R<sub>L<\/sub> + J X<sub>C<\/sub> = R<sub>s<\/sub> + J X<sub>L\u00a0 <\/sub>(8)<\/p>\n<p>Equation (7) indicates that if the source is inductive, the load must be capacitive of equal magnitude in addition to equal resistors. This is in fact the series resonance effect as is expected. Please refer to problem section for derivation of above equations.<\/p>\n<p><strong>2. Methodologies<\/strong><\/p>\n<p>Several methods are available to match or to convert the load impedance\/resistance to that of the source to obtain maximum power depending on the circuit configurations and the frequency of interest. The remaining of this series will be devoted to the development, theory, and the techniques of these methods.<\/p>\n<p><strong>2.1. Transformer Method<\/strong> -Two types of transformers, which are used, for impedance matching and impedance conversion to optimize receiver&#8217;s power are shown in Fig 4.<\/p>\n<p>Laminated ferrite core transformers are used in the output stages of audio amplifiers to match the high output impedances of the output stages to the low input impedance (typically 4, 6, 8, and 12 ohms) of the speakers while ferrite coils are used mostly in the I.F. stages of R.F. amplifiers. Regardless which device is used, the primary object is the determination of the turn ratio of the transformer to deliver maximum power to the load. Referring to Fig 4 (a), the transformer turn ratio can be determined as follows;<\/p>\n<p style=\"padding-left: 40px;\"><img loading=\"lazy\" class=\"wp-image-5733\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/audio-transformers-work-well-for-matching-low-33.jpeg\" alt=\"... audio transformers work well for matching low impedance headsets from\" width=\"290\" height=\"183\" \/><img loading=\"lazy\" class=\"wp-image-5734\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-appdata-local-temp-wpdnse-019d0113-01-33.jpeg\" alt=\"C:\\Users\\mm\\AppData\\Local\\Temp\\WPDNSE\\{019D0113-0188-018C-7A01-6F01F700F500}\\20150208_175433.jpg\" width=\"332\" height=\"182\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-appdata-local-temp-wpdnse-019d0113-01-33.jpeg 432w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-appdata-local-temp-wpdnse-019d0113-01-33-300x164.jpeg 300w\" sizes=\"(max-width: 332px) 100vw, 332px\" \/><\/p>\n<p>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(a)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (b)<\/p>\n<p style=\"padding-left: 320px;\"><img loading=\"lazy\" width=\"49\" height=\"49\" class=\"wp-image-5735\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-377.png\" \/><\/p>\n<p>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (c)<\/p>\n<p style=\"text-align: center;\"><strong>Fig. 4 Transformers (a) Ferrite core transformer (b) ferrite coils, two small I.F. coils (red and yellow colors) are used in the bases of transistors for impedance conversion. (c)Transformer representation.<\/strong><\/p>\n<p><img loading=\"lazy\" width=\"157\" height=\"19\" class=\"wp-image-5736\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-v_1-i_1-1-33.gif\" alt=\"Z_{in}= V_{1}\/I_{1}\\: \\: \\: \\: \\: \\: \\: \\: \\: \\: \\: (9)\" \/><\/p>\n<p>Using general voltage-turn ratio:<\/p>\n<p><img loading=\"lazy\" width=\"310\" height=\"19\" class=\"wp-image-5737\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/v_1-v_2-n_1-n_2-i_1-i_2-n_2-n_-33.gif\" alt=\"V_{1}\/V_{2}= N_{1}\/N_{2}.....I_{1}\/I_{2}= N_{2}\/N_{1}\\: \\: \\: \\: \\: (10)\" \/><\/p>\n<p>in equation (9), we obtain:<\/p>\n<p><img loading=\"lazy\" width=\"227\" height=\"21\" class=\"wp-image-5738\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-v_2-i_2n_1-n_22-1-33.gif\" alt=\"Z_{in}= V_{2}\/I_{2}(N_{1}\/N_{2})^{2}\\: \\: \\: \\: \\; \\: \\: \\: (11)\" \/><\/p>\n<p>But since <img loading=\"lazy\" width=\"75\" height=\"15\" class=\"wp-image-5739\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/v_2-i_2z_2-33.gif\" alt=\"V_{2}= I_{2}Z_{2}\" \/>, equation (11) transforms to:<\/p>\n<p><img loading=\"lazy\" width=\"211\" height=\"21\" class=\"wp-image-5740\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-z_1n_1-n_22-1-33.gif\" alt=\"Z_{in}= Z_{1}(N_{1}\/N_{2})^{2}\\, \\, \\, \\, \\, \\: \\: \\: \\: \\: \\: (12)\" \/><\/p>\n<p>This impedance must match the source impedance, Zs, as shown in Fig 3. Thus,<\/p>\n<p><img loading=\"lazy\" width=\"236\" height=\"21\" class=\"wp-image-5741\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-z_s-z_ln_1-n_22-1-33.gif\" alt=\"Z_{in}= Z_{s}= Z_{L}(N_{1}\/N_{2})^{2}\\, \\, \\, \\, \\, \\: (13)\" \/><\/p>\n<p>Finally optimum turn ratio to deliver maximum power to the load becomes;<\/p>\n<p>N<sub>1<\/sub>\/N<sub>2<\/sub> = \u221a Z<sub>s<\/sub>\/Z<sub>L<\/sub> \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(14)<\/p>\n<p>Note: Above derivation have not taken losses in to consideration. Transformer are not 100% efficient, their losses should not exceed 3% of their rated power capacity. These losses are;<\/p>\n<p style=\"padding-left: 40px;\">1. Eddy current losses due to circulating current in the ferrite material. It varies as the square of frequency and the flux density according to following equation [1, 2];<\/p>\n<p style=\"padding-left: 40px;\"><img loading=\"lazy\" width=\"168\" height=\"22\" class=\"wp-image-5742\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/p_eddykb2f2-15-33.gif\" alt=\"P_{eddy}=kB^{2}f^{2}\\: \\: \\: \\: \\: \\: (15)\" \/><\/p>\n<p style=\"padding-left: 40px;\">k is a material and geometry constant.<\/p>\n<p style=\"padding-left: 40px;\">This loss can be reduced by using laminated ferrite.<\/p>\n<p style=\"padding-left: 40px;\">2. Hysteresis losses due to energy lost in aligning magnetic domain of\u00a0the core material. It varies linearly with frequency and exponentially with the flux;<\/p>\n<h3 style=\"padding-left: 40px;\"><img loading=\"lazy\" width=\"141\" height=\"18\" class=\"wp-image-5744\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/p_h-eta-fbn-16-33.gif\" alt=\"P_{h}=\\eta fB^{n}\\, \\, \\: \\: \\: \\: (16)\" \/><sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0<\/sup><\/h3>\n<p style=\"padding-left: 40px;\">\u03b7 is a constant<\/p>\n<p style=\"padding-left: 40px;\">This loss can be reduced by selecting a good grade ferrite.<\/p>\n<p style=\"padding-left: 40px;\">In addition to their frequency dependent losses, transformers are, in general, heavy and bulky, gradually dying out, replacing with new technology, except in power transmission.<\/p>\n<p><strong>2.2. Transmission Line Method:<\/strong> T-lines are used for impedance matching in R.F. more efficiently where the use of transformer, due to shorter wavelength, becomes impractical. For example a short segment (5-10 centimeter) of T-lines such as RG 59 with characteristic impedance of Z<sub>c<\/sub>\u255075\u03a9 can accomplish the same task as ferrite core transformer with negligible losses because, as will be demonstrated in the following, they can be used as a capacitor or as an inductor depending on their lengths and terminations, to optimize the power. Following is a review of T-line theory and applications for impedance matching.<\/p>\n<p>Exploring T-line Theory: Consider a lossless short segment of a T-line terminated with load Z<sub>L<\/sub> shown in Fig. 5, which is the same as Fig. 3 except for the connecting cable with characteristic impedance of Z<sub>c<\/sub> assumed to be lossless.<\/p>\n<p style=\"padding-left: 80px;\"><img loading=\"lazy\" class=\"wp-image-5745\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-downloads-20150210_160303-1-jpg-33.jpeg\" alt=\"C:\\Users\\mm\\Downloads\\20150210_160303-1.jpg\" width=\"205\" height=\"148\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-downloads-20150210_160303-1-jpg-33.jpeg 371w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-downloads-20150210_160303-1-jpg-33-300x217.jpeg 300w\" sizes=\"(max-width: 205px) 100vw, 205px\" \/><img loading=\"lazy\" class=\"wp-image-5746\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-378.png\" width=\"411\" height=\"139\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-378.png 301w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-378-300x102.png 300w\" sizes=\"(max-width: 411px) 100vw, 411px\" \/><\/p>\n<p>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(a)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(b)<\/p>\n<p style=\"text-align: center;\"><strong>Fig. 5 (a) Some H.F. T-line (b) T-line terminated with a load impedance Z<sub>L<\/sub><\/strong><\/p>\n<p>The input impedance of this line is given by [3];<\/p>\n<p><img loading=\"lazy\" width=\"289\" height=\"44\" class=\"wp-image-5747\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-z_c-fracz_ljz_ctan2pl-lambda-66.gif\" alt=\"Z_{in}= Z_{c}\\frac{Z_{L}+JZ_{c}tan(2Pl\/\\lambda )}{Z_{c}+JZ_{L}tan(2Pl\/\\lambda)}\\: \\: \\: \\: \\: \\: (17)\" \/><\/p>\n<p>l is the line length<\/p>\n<p>\u03bb is the wave length<\/p>\n<p>This impedance is function of length, frequency, and the load impedance, Z<sub>L. <\/sub>Two types of terminations are of interest:<\/p>\n<p>2.2.1. Short Circuited T-line, Z<sub>L<\/sub>=0; for this case Z <sub>in<\/sub> simplifies to<\/p>\n<p><img loading=\"lazy\" width=\"213\" height=\"19\" class=\"wp-image-5748\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-jz_ctan2-pi-l-lambda-1-33.gif\" alt=\"Z_{in}= JZ_{c}tan(2\\pi l\/\\lambda )\\, \\, \\, \\, \\, \\, (18)\" \/><\/p>\n<p>Depending on the length of the line, two cases may happen:<\/p>\n<p><img loading=\"lazy\" width=\"341\" height=\"19\" class=\"wp-image-5749\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in0-l-lambda-2-series-res-33.gif\" alt=\"Z_{in}=0,\\: \\, \\, l=\\lambda \/2,\\: \\: \\: Series Resonance\\, \\, \\, (19a)\" \/><\/p>\n<p><img loading=\"lazy\" width=\"364\" height=\"19\" class=\"wp-image-5750\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-infty-l-lambda-4-para-33.gif\" alt=\"Z_{in}=\\infty ,\\, \\, \\, l=\\lambda \/4,\\: \\: \\: Parallel Resonance\\, \\, \\: (19b)\" \/><\/p>\n<p>For this case, T-line acts like lumped element parallel or series resonance circuit depending on its length. For example, a quarter wavelength short terminated T-lines can be inserted in the base of an amplifier to obtain an oscillation without a positive feedback [4].<\/p>\n<p>2.2.2. Open Circuited T- line: Z<sub>L<\/sub> = \u221e, for this case Z <sub>in<\/sub> can be written as:<\/p>\n<p><img loading=\"lazy\" width=\"285\" height=\"53\" class=\"wp-image-5751\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_inz_c-frac1j-fracz_ctan2-pi-l-lambda-33.gif\" alt=\"Z_{in}=Z_{c}\\frac{1+J\\frac{Z_{c}tan(2\\pi l\/\\lambda )}{Z_{L}}}{Z_{c}\/Z_{L}+Jtan(2\\pi l\/\\lambda )}\\: \\: \\: \\: (20)\" \/><\/p>\n<p>Or<\/p>\n<p><img loading=\"lazy\" width=\"209\" height=\"42\" class=\"wp-image-5752\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-j-fracz_ctan2-pi-l-lambda-1-33.gif\" alt=\"Z_{in}=-J\\frac{Z_{c}}{tan(2\\pi l\/\\lambda )}\\, \\, \\, \\, \\, (21)\" \/><\/p>\n<p>The lumped element equivalent circuit of this line is now a capacitor.<\/p>\n<p>Above cases are tabulated in table 2.<\/p>\n<p style=\"text-align: center;\"><strong>Table 2-Lumped element equivalent circuits representations of terminated T-lines<\/strong><\/p>\n<table>\n<tbody>\n<tr>\n<td>Type of Termination<\/td>\n<td>\u00a0 \u00a0 \u00a0L=\u03bb\/4\u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u03bb\/4\u02c2L\u02c2\u03bb\/2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0L=\u03bb\/2<\/td>\n<\/tr>\n<tr>\n<td>Short<\/p>\n<p>Open<\/td>\n<td><img loading=\"lazy\" width=\"329\" height=\"86\" class=\"wp-image-5753\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-379.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-379.png 329w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-379-300x78.png 300w\" sizes=\"(max-width: 329px) 100vw, 329px\" \/><img loading=\"lazy\" width=\"321\" height=\"82\" class=\"wp-image-5754\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-380.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-380.png 321w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-380-300x77.png 300w\" sizes=\"(max-width: 321px) 100vw, 321px\" \/><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>2.2.3. Quarter-wave Transformer: One case of particular interest, which is being used extensively by R.F. and communication engineers, is the quarter-wave section terminated in any general load, Z<sub>L<\/sub>. For this case\u00a0 with l = \u03bb\/4, equation (17) transforms to;<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?Z_{in}=&amp;space;Z_{c}\\frac{Z_{L}\/tan(\\pi&amp;space;\/2)+JZ_{c}}{Z_{c}\/tan(\\pi&amp;space;\/2)+JZ_{L}}=&amp;space;\\frac{Z_{c}^{2}}{Z_{L}}\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;17-1&amp;space;\\right&amp;space;)\" alt=\"Z_{in}= Z_{c}\\frac{Z_{L}\/tan(\\pi \/2)+JZ_{c}}{Z_{c}\/tan(\\pi \/2)+JZ_{L}}= \\frac{Z_{c}^{2}}{Z_{L}}\\, \\, \\, \\, \\, \\left ( 17-1 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>Thus, a quarter-wave T-line acts as an impedance inverter. If the input impedance consisted of a resistance R<sub>L<\/sub> in series with an inductive reactance X<sub>L<\/sub>, it will be transferred to a resistance R<sub>s<\/sub> in parallel with a capacitive reactance X<sub>c<\/sub> where<\/p>\n<p>R<sub>s<\/sub> = R<sub>c<\/sub><sup>2<\/sup>\/R<sub>L<\/sub> and X <sub>c <\/sub>= R<sub>c<\/sub><sup>2<\/sup>\/X<sub>L\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <\/sub>(22)<\/p>\n<p>Still another important and practical property of quarter-wave T-line can be extracted from equation (21) by matching Z <sub>in<\/sub> to Z<sub>s<\/sub>, we obtain;<\/p>\n<p>Z <sub>c<\/sub> = \u221a Z<sub>s<\/sub> Z<sub>L\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <\/sub>\u00a0(23)<\/p>\n<p>The interpretation is that if we insert a quarter-wave T-line with characteristic impedance given by equation (23) between the load and the source, no matter what the nature of the load, it will be matched to the source impedance as long as geometry permits.<\/p>\n<p>A word of caution: Generally Z<sub>c<\/sub> is considered to be a pure lossless resistor, thus the product of Z<sub>s<\/sub>Z<sub>L<\/sub> must be real. This requires, except one case, (see problem section), that the load and the source must be pure resistive. In that case, we should transform the above equation to:<\/p>\n<p>R<sub>c<\/sub> = \u221a R<sub>L<\/sub> R<sub>s<\/sub> (24)<\/p>\n<p>This relation will be used in Example 1. Although our analysis is for single frequency, they can also be used for broadband matching, but the procedure is a little complicated. Interested reader should consult the reference given at the end of this series [5].<\/p>\n<p>2.2.4. Pure Input Resistance: Along the loaded T \u2013 line, there is a location where the input impedance, Z<sub>in<\/sub>, becomes purely resistive regardless of the nature of the load. This is the most interesting part of T- line applications. This feature will be used for impedance matching as will be demonstrated in the examples to follow. Theoretically, the location, l, can be determined from equation (17) by replacing Z<sub>in<\/sub> with a pure resistance as;<\/p>\n<p><img loading=\"lazy\" width=\"285\" height=\"44\" class=\"wp-image-5755\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_inz_c-fracz_ljz_ctan2-pi-l-lambda-63.gif\" alt=\"Z_{in}=Z_{c}\\frac{Z_{L}+JZ_{c}tan(2\\pi l\/\\lambda )}{Z_{c}+JZ_{L}tan(2\\pi l\/\\lambda )}\\: \\: \\: \\: \\: \\: (17)\" \/><\/p>\n<p>Or\u2026\u2026. Z<sub>in<\/sub>=R<sub>in<\/sub><\/p>\n<p>The derivation is quite complicated, (refer to problem section). Example 1 will demonstrate its application graphically.<\/p>\n<p>2.2.5. Stub-Matching<strong>: <\/strong>There are several methods such as T-Match, Gamma Match, and Omega Match of using T-lines for impedance conversion [6]. Stub matching explained in the following is the most popular one. This method has two configurations shown in Fig. 6; series and shunt stub matching. Regardless which method is used, d1, d2, R<sub>c<\/sub> and x must be determined analytically, either graphically, or by simulation. Analytical method is lengthy, graphical and simulation methods are preferred. Following is a short description of graphical method referred to as Smith chart used inclusively by all communication engineers.<\/p>\n<p style=\"padding-left: 120px;\"><img loading=\"lazy\" class=\"wp-image-5756\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/http-javan-courses-wp-content-uploads-2019-05-wo-2.png\" alt=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-355.png\" width=\"231\" height=\"82\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/http-javan-courses-wp-content-uploads-2019-05-wo-2.png 310w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/http-javan-courses-wp-content-uploads-2019-05-wo-2-300x106.png 300w\" sizes=\"(max-width: 231px) 100vw, 231px\" \/><img loading=\"lazy\" class=\"wp-image-5757\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/http-javan-courses-wp-content-uploads-2019-05-wo-3.png\" alt=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-356.png\" width=\"247\" height=\"112\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/http-javan-courses-wp-content-uploads-2019-05-wo-3.png 325w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/http-javan-courses-wp-content-uploads-2019-05-wo-3-300x136.png 300w\" sizes=\"(max-width: 247px) 100vw, 247px\" \/><\/p>\n<p style=\"padding-left: 80px;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (a)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (b)<\/p>\n<p style=\"text-align: center;\"><strong>Fig. 6 Stub matching (a) series quarter-wave matching (b) shunt matching.<\/strong><\/p>\n<p style=\"text-align: center;\">Note: in (a) we have used real load, RL and real source Rs as mentioned earlier.<\/p>\n<p>The Smith Chart: Introduced in 1939 is an indispensable graphical representation for impedance analysis [7]. Internet has excellent references with ample examples and descriptions [8]. The Chart is mapping the Z plane, (x, y) coordinates to \u0393 (reflection plane) with (u, v) coordinate according to following two equations [9].<\/p>\n<p><img loading=\"lazy\" width=\"278\" height=\"39\" class=\"wp-image-5758\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/u-fracrr12v2-frac1r12-1-33.gif\" alt=\"(u-\\frac{r}{r+1})^{2}+v^{2}=(\\frac{1}{r+1})^{2}\\: \\: \\: \\: \\: \\: (25)\" \/><\/p>\n<p><img loading=\"lazy\" width=\"253\" height=\"37\" class=\"wp-image-5759\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/u-12v-frac1x2-frac1x2-1-33.gif\" alt=\"(u-1)^{2}+(v-\\frac{1}{x})^{2}=\\frac{1}{x^{2}}\\: \\: \\: \\: \\; \\; (26)\" \/><\/p>\n<p>These are the equations of two circles with changing radii and the centers; see the attached charts Fig. 7 and 8. It is indeed a challenging task to use a program to plot these circles. We have used Q basic and have obtained partial plots of these circles [10]. On these plots, horizontal circles represent the real part of Z, and the positive\/negative vertical circles represent the inductive\/capacitive part of the Z. Intersection of these two circles will give the real and the imaginary parts of the Z. Extreme left on the x-axis represent Z=0, the one on the extreme right with smallest radios is Z = \u221e. The center of the chart presents a perfect match. The whole circle is \u03bb\/2. The chart is normalized, so that extracted number from the chart should be multiply by the reference impedance. This condensed description will be exploded with the following two examples.<\/p>\n<p><strong><img loading=\"lazy\" width=\"640\" height=\"640\" class=\"wp-image-5760 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-smith_chart_gen_svg-png-33.png\" alt=\"C:\\Users\\mm\\Desktop\\Smith_chart_gen_svg.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-smith_chart_gen_svg-png-33.png 640w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-smith_chart_gen_svg-png-33-150x150.png 150w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-smith_chart_gen_svg-png-33-300x300.png 300w\" sizes=\"(max-width: 640px) 100vw, 640px\" \/><\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 7 Original Smith Chart [11]<\/strong><\/p>\n<p><strong><img loading=\"lazy\" class=\"wp-image-5761 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_22-img-tif-33.jpeg\" alt=\"C:\\Users\\mm\\Desktop\\2015_01_22\\IMG.tif\" width=\"641\" height=\"867\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_22-img-tif-33.jpeg 1262w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_22-img-tif-33-222x300.jpeg 222w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_22-img-tif-33-768x1039.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_22-img-tif-33-757x1024.jpeg 757w\" sizes=\"(max-width: 641px) 100vw, 641px\" \/><\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Fig.8 Mechanical Smith chart with added features [12]<\/strong><\/p>\n<p><strong>Example 1:<\/strong><\/p>\n<p><strong>Graphical method<\/strong><\/p>\n<p>Given: Z<sub>L<\/sub> = 100 + J 60, Z<sub>s<\/sub>=50, f=1 GHz<\/p>\n<p>Determine: d, Z<sub>c<\/sub>, l, using series stub matching<\/p>\n<p><img loading=\"lazy\" width=\"310\" height=\"110\" class=\"wp-image-5762 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-381.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-381.png 310w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-381-300x106.png 300w\" sizes=\"(max-width: 310px) 100vw, 310px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 9 Circuit for example 1<\/strong><\/p>\n<p>Solution:<\/p>\n<p>Notes: As mentioned above, series stub matching uses quarter-wave transformer. With Z<sub>s<\/sub> being real, it only matches the real resistances according to equation (24). Thus, we must move from the load toward the source until we locate pure input resistance, this distance will be d1. Refer to the Smith chart below. The procedure is following:<\/p>\n<p style=\"padding-left: 40px;\">1. Normalize Z<sub>L<\/sub>, Z<sub>N <\/sub>= (100 + J 60) \/50 = 2 + J 1.2, enter on S.C. point A, Fig. 10.<\/p>\n<p style=\"padding-left: 40px;\">2. Draw a circle, radios OA, This is called VSWR circle, (it will not change as long as Z<sub>L<\/sub> is not changed).<\/p>\n<p style=\"padding-left: 40px;\">3. Move around this circle C.W. (toward the source) until you cross the x-axis. Here Z<sub>in<\/sub> is pure resistive, d is:<\/p>\n<p style=\"padding-left: 40px;\">d \u2550 0.25\u03bb \u2500 0.21\u03bb \u2550 0.04\u03bb<\/p>\n<p>The magnitude of d is not practical on T-line. This is due to the selected frequency, shorter \u03bb. The example is in fact calls for the use of micro strip T-line elements, which will be discussed below in example 2 for the same information given in this example. However, the above outlined procedure remains valid.<\/p>\n<p style=\"padding-left: 40px;\">4. Read the value of the input resistance, x crossing, (3), point B, and then de-normalize it with 50\u03a9 to obtain the real input resistance;<\/p>\n<p style=\"padding-left: 40px;\">R<sub>in<\/sub> \u2550 50 x 3 \u2550 150\u03a9<\/p>\n<p style=\"padding-left: 40px;\">5. Calculate R<sub>c<\/sub>, equation (24);\u00a0 \u00a0 \u00a0R<sub>c<\/sub> \u2550 \u221a R<sub>in<\/sub> R<sub>s<\/sub> \u2550 \u221a150 x 50 \u2550 86.6\u03a9<\/p>\n<p style=\"padding-left: 40px;\">6. Find l\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0l \u2550 \u03bb\/4 \u2550 7.5 cm @ f=1 GHz<\/p>\n<p><strong>Conclusion: <\/strong>If we insert a coaxial cable between the load and the source with the characteristic impedance R<sub>c<\/sub> \u2550 86.6\u03a9 and length 7.5 cm at a distance d1\u25501.2 cm from the load, the load will be matched to the source i.e. the locus of the impedance will fall immediately to the center of the chart indicating perfect match as will be verified using interactive simulation software below. Unfortunately, it is not always possible to find a coax with the exact value of R<sub>c<\/sub>, but any cable with closer value will perform satisfactory. The closes cable for this case is RG-7\/U, RG-22\/U, RG-62\/U, RG-71\/U, or RG-111\/U [13].<\/p>\n<p>Series stub matching is not practical, cable must be cut, and terminal connections may introduce error. Shunt stub matching explained in example 2 is preferable.<\/p>\n<p><strong><img loading=\"lazy\" width=\"1379\" height=\"1186\" class=\"wp-image-5763\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_30-img_new-jpg-33.jpeg\" alt=\"C:\\Users\\mm\\Desktop\\2015_01_30\\IMG_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_30-img_new-jpg-33.jpeg 1379w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_30-img_new-jpg-33-300x258.jpeg 300w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_30-img_new-jpg-33-768x661.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_30-img_new-jpg-33-1024x881.jpeg 1024w\" sizes=\"(max-width: 1379px) 100vw, 1379px\" \/><\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 10 Smith chart for example 1<\/strong><\/p>\n<p><strong>Example 2: <\/strong><\/p>\n<p><strong><em>Graphical method<\/em><\/strong><\/p>\n<p>Given: Z<sub>L<\/sub> = 100 + J 60, Z<sub>s<\/sub>=50, f=1 GHz, (same as Example 1).<\/p>\n<p>Determine: d1, d2, and X, using shunt stub matching<\/p>\n<p><img loading=\"lazy\" width=\"325\" height=\"147\" class=\"wp-image-5764 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-382.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-382.png 325w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-382-300x136.png 300w\" sizes=\"(max-width: 325px) 100vw, 325px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig 11. Circuit for example 2<\/strong><\/p>\n<p>Solution:<\/p>\n<p style=\"padding-left: 40px;\">1. Normalize Z<sub>L<\/sub>: Z<sub>N<\/sub> = 100 + J60\/50 = 2 + J1.2, enter Smith chart, Z<sub>N<\/sub>, Fig.12<\/p>\n<p style=\"padding-left: 40px;\">2. Draw VSWR circle, radius OA,<\/p>\n<p style=\"padding-left: 40px;\">3. Draw line from A to O, extend until crossing VSWR circle, point B, this is Y<sub>N<\/sub>.<\/p>\n<p>Shunt matching is easier using Y instead Z. Opposite to Z is Y, Smith chart has this feature.<\/p>\n<p style=\"padding-left: 40px;\">4. Now move C.W. toward the source until you cross the horizontal circle r = 1, point C. AT this point, the input conductance is matched to the source conductance.<\/p>\n<p style=\"padding-left: 40px;\">Y<sub>N<\/sub> = 1 + J 1.1<\/p>\n<p style=\"padding-left: 40px;\">d1 = (0.374 + 0.04) \u03bb<\/p>\n<p style=\"padding-left: 40px;\">\u03bb = c\/ f = 3 x 10<sup>10<\/sup> \/1 x 10<sup>9<\/sup> = 30 cm<\/p>\n<p style=\"padding-left: 40px;\">d1 = 12.42 cm<\/p>\n<p style=\"padding-left: 40px;\">5. Now must add a capacitive reactance to cancel the inductive reactance, J1.1. This will be done by using a short-circuited T- line. Start from Y=0 move C.W. around the outer circle until you locate B<sub>c <\/sub>= &#8211; 1.1\/50, thus X<sub>c<\/sub>= -50\/1.1= -45.45.<\/p>\n<p style=\"padding-left: 40px;\">6. Determine; d2 = 0.116\u03bb = 3.48cm<\/p>\n<p>By adding this short-circuited T-line, final locus will fall on the center of the Smith chart indicating perfect match. It is quite interesting to observe this using simulation as will be shown next.<\/p>\n<p><img loading=\"lazy\" width=\"1379\" height=\"1416\" class=\"wp-image-5765\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_31-img_0009_new-jpg-33.jpeg\" alt=\"C:\\Users\\mm\\Desktop\\2015_01_31\\IMG_0009_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_31-img_0009_new-jpg-33.jpeg 1379w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_31-img_0009_new-jpg-33-292x300.jpeg 292w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_31-img_0009_new-jpg-33-768x789.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_31-img_0009_new-jpg-33-997x1024.jpeg 997w\" sizes=\"(max-width: 1379px) 100vw, 1379px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 12 Smith chart for example 2<\/strong><\/p>\n<p><strong>Example 2:<\/strong><\/p>\n<p><strong>Simulation<\/strong><\/p>\n<p>Given:\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Z<sub>L<\/sub> = 100 + J 60, Z<sub>s<\/sub>=50, f=1 GHz<\/p>\n<p>Determine:\u00a0 \u00a0 \u00a0 \u00a0 d1, d2, and X, using shunt stub matching<\/p>\n<p>Solution:<\/p>\n<p>We have used MIMP and determined all the unknowns of above example by interactively tuning the elements until locus falls on the center of the Smith chart [14]. Interactive tuning of the elements is the most outstanding feature of this software. There are three screens on this program. Procedure is as follows;<\/p>\n<p style=\"padding-left: 40px;\">Screen 1: Enter load and source impedance entry, Z<sub>L<\/sub> and Z<sub>s<\/sub>.<\/p>\n<p style=\"padding-left: 40px;\">Screen 2: Select micro strip elements, this is d1, and d2, and x.<\/p>\n<p style=\"padding-left: 40px;\">Screen 3: display Smith chart and tune the elements interactively until locus falls on the center of the S.C.<\/p>\n<p>Please see the attached screen shots, Fig.13, 14, and 15 for verification.<\/p>\n<p><img loading=\"lazy\" width=\"1182\" height=\"1743\" class=\"wp-image-5766\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0001-tif-33.jpeg\" alt=\"C:\\Users\\mm\\Desktop\\2015_01_21\\IMG_0001.tif\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0001-tif-33.jpeg 1182w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0001-tif-33-203x300.jpeg 203w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0001-tif-33-768x1133.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0001-tif-33-694x1024.jpeg 694w\" sizes=\"(max-width: 1182px) 100vw, 1182px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 13 Example 2- Simulation, MIMP<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Screen 1- load and source entry<\/strong><\/p>\n<p><img loading=\"lazy\" width=\"1279\" height=\"1718\" class=\"wp-image-5767\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img-tif-33.jpeg\" alt=\"C:\\Users\\mm\\Desktop\\2015_01_21\\IMG.tif\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img-tif-33.jpeg 1279w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img-tif-33-223x300.jpeg 223w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img-tif-33-768x1032.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img-tif-33-762x1024.jpeg 762w\" sizes=\"(max-width: 1279px) 100vw, 1279px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 14 Example 2 \u2013 Simulation-MIMP <\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Screen 2- stub entry<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>W\/L micro strip width\/length<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>90.99\/62 characteristic impedances of strip lines<\/strong><\/p>\n<p><img loading=\"lazy\" width=\"1286\" height=\"1789\" class=\"wp-image-5768\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0003-tif-33.jpeg\" alt=\"C:\\Users\\mm\\Desktop\\2015_01_21\\IMG_0003.tif\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0003-tif-33.jpeg 1286w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0003-tif-33-216x300.jpeg 216w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0003-tif-33-768x1068.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_21-img_0003-tif-33-736x1024.jpeg 736w\" sizes=\"(max-width: 1286px) 100vw, 1286px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 15 Example 2-Simulation- MIMP<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Screen 3 <\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Smith chart display<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Note: Final locus is on chart center indicating perfect match<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Table 3- Comparison of graphical and simulation results for example 2<\/strong><\/p>\n<table>\n<tbody>\n<tr>\n<td>Component<\/td>\n<td>Graphical<\/td>\n<td>Simulation<\/td>\n<\/tr>\n<tr>\n<td>d1\/Z<\/td>\n<td>0.414\u03bb\/50<\/td>\n<td>0.313\u03bb\/90<\/td>\n<\/tr>\n<tr>\n<td>d2\/Z<\/td>\n<td>0.116\u03bb\/50<\/td>\n<td>0.210\u03bb\/62<\/td>\n<\/tr>\n<tr>\n<td>X<sub>c<\/sub><\/td>\n<td>45.45<\/td>\n<td>62<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><strong>2.3. Solid State Electronics <\/strong>\u2013 Impedance Conversion: Since its birth, transistor has been used in several segments of technology. Its applications include<\/p>\n<p style=\"padding-left: 40px;\">1. as an amplifier \u2013 (analog electronics)<\/p>\n<p style=\"padding-left: 40px;\">2. as a switch \u2013 (digital electronics)<\/p>\n<p style=\"padding-left: 40px;\">3. As a constant current source \u2013 (power supply)<\/p>\n<p style=\"padding-left: 40px;\">4. as an impedance converter (analog electronics)<\/p>\n<p style=\"padding-left: 40px;\">5. as a level shifter (digital electronics)<\/p>\n<p>In this series, we will consider only the impedance converter; hopefully readers are familiar with the basic principles of transistor.<\/p>\n<p>Transistors are used in three different modes;<\/p>\n<p style=\"padding-left: 40px;\">1. Common emitter<\/p>\n<p style=\"padding-left: 40px;\">2. Common collector \u2013 (emitter follower)<\/p>\n<p style=\"padding-left: 40px;\">3. Common base<\/p>\n<p>Each mode has its own different parameters such as; input\/output impedances, voltage &#8211; current gain, and power. These parameters are different for each mode. For example common collector has no voltage gain but posses high input impedance with low output impedance. On the other hand, common emitter has moderate voltage and current gain with moderate input\/output impedances. Common base has no current gain but indicates negative resistance, which is used in H.F. oscillator [15]. Our primary concern will be the application of common collector (emitter follower) for impedance conversion. Consider a common collector configuration shown in Fig. 16.<\/p>\n<p><img loading=\"lazy\" width=\"461\" height=\"217\" class=\"wp-image-5769 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-383.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-383.png 461w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-383-300x141.png 300w\" sizes=\"(max-width: 461px) 100vw, 461px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig 16-Common collector (emitter follower) configurations<\/strong><\/p>\n<p>The input and the output impedances of this configuration are given approximately by [16];<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?R_{in}\\approx&amp;space;h_{fe}R_{e},\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;R_{o}\\approx&amp;space;R_{s}\/h_{fe}\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;27&amp;space;\\right&amp;space;)\" alt=\"R_{in}\\approx h_{fe}R_{e},\\, \\, \\, \\, \\, R_{o}\\approx R_{s}\/h_{fe}\\, \\, \\, \\, \\, \\left ( 27 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>h<sub>fe<\/sub> is the small signal current gain; its value ranges from 50 \u2013 200. For a nominal value of 100, if we insert a resistor Re = 10 Ohms in the emitter, the input impedance will be R<sub>in<\/sub> \u2248 1 k. On the other hand, for a source resistance of 1 k, the output impedance will be 10 Ohms. It is clear from this short analysis that a common collector (emitter follower) can be used as an impedance converter, and this is in fact the case. Generally, in audio amplifier, a speaker with impedance of (4, 8, 12, 16 ohms) is inserted in the emitter. This will insure impedance conversion and thus transfer of maximum power to the speaker.<\/p>\n<p>Note: Rin and Ro refers to ac quantities, thus, it is important in measuring these parameters, batries (DC) sources must be removed.<\/p>\n<p>The main drawbacks of transistors for impedance matching are their low power ratings. However, with a different configuration such as push-pull or push-push amplifiers this limitation can be controlled to a certain extent [17].<\/p>\n<p><strong>2.4. Antenna Impedance Matching;<\/strong> Antennas are used in wireless communication to intercept the information contained in the radiated field of electromagnetic waves. Electromagnetic field contains energy; this energy will induce moving charges in the antenna, thus producing current and signals. As mentioned in the introduction section, these signals are extremely low in amplitudes, thus requiring amplifications. One way to amplify these signals is to match the antenna impedance to the electromagnetic impedance of radiated wave. Electromagnetic field is a complex science so is the antenna theory and design; they both possess impedances, which will be discussed shortly. For now, we mention that Marconi&#8217;s achievement would not be possible without a radiating instrument, the antenna [18]. Truly antennas are the most important and exciting component of electronics.<\/p>\n<p>Originally, antennas were made from piece of wires in different shapes and configuration. But during the last two decades, advancement in electronic technology has opened a new exciting era in the development and designing of antennas using conducting sheets in different geometrical configurations such as microstrip and IF (inverted F ) antennas as they are used in cell phones and mobile communications [19].<\/p>\n<p>Radiation principle: Consider a capacitor connected to an AC signal as shown in Fig. 17.<\/p>\n<p><img loading=\"lazy\" width=\"482\" height=\"105\" class=\"wp-image-5770 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-384.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-384.png 482w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-384-300x65.png 300w\" sizes=\"(max-width: 482px) 100vw, 482px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 17 Radiation principle (a) capacitor charging and discharging in an AC circuit (b) the circuit is used as radiating element<\/strong><\/p>\n<p>In contrast to DC, in AC circuit, capacitor charges, discharges to the air, its energy is transferred to the air in the form of electromagnetic waves. This is the energy which receiving antenna will intercept, and the information contained in the signal will be extracted. Circuit has impedance, so does the radiated wave, which is discussed in equation (31).<\/p>\n<p>Note: Although we used capacitor as a radiating element, but for strong radiation they are removed. Sharper corners are better radiators. Also, note that antennas are reciprocal, i.e. the same antenna can be used for radiation and detection.<\/p>\n<p>2.4.1. Half \u2013 Wave dipole: One type of antenna, which will be reshaped later for impedance matching, are shown in Fig. 18 assuming sine wave excitation.<\/p>\n<p><img loading=\"lazy\" width=\"1258\" height=\"693\" class=\"wp-image-5771\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new-jpg-6.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new-jpg-6.jpeg 1258w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new-jpg-6-300x165.jpeg 300w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new-jpg-6-768x423.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new-jpg-6-1024x564.jpeg 1024w\" sizes=\"(max-width: 1258px) 100vw, 1258px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 18 \u2013 A Half-wave dipole antenna with assumed sinusoidal signal source<\/strong><\/p>\n<p>With assumed sine wave excitation, the current distribution along the antenna will also be a sine wave (2\u03c0 = \u03bb) as shown but the length of the dipole will be (\u03c0) or;<\/p>\n<p>l \u2550 \u03bb\/2 (28)<\/p>\n<p>\u03bb is the wavelength given by;<\/p>\n<p>\u03bb \u2550 c\/ f (29)<\/p>\n<p><em>c<\/em> \u2550 3 x 10^8 m\/sec, speed of E\/W<\/p>\n<p><em>f\u00a0 <\/em>the frequency in Hz<\/p>\n<p>Once the frequency is specified, the length of the antenna can be determined from equation (29, 28). Theoretically, every dipole is designed for a certain frequency. However, in practice, a given antenna will pick up several stations within proximity frequencies.<\/p>\n<p>The radiation impedance (not the physical) of half-wave dipole is given by;<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?R_{r}=&amp;space;\\frac{P_{r}}{I_{o}^{2}}\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;30&amp;space;\\right&amp;space;)\" alt=\"R_{r}= \\frac{P_{r}}{I_{o}^{2}}\\, \\, \\, \\, \\, \\left ( 30 \\right )\" align=\"absmiddle\" \/><\/p>\n<p><em>P<sub>r<\/sub> <\/em>is the radiated power and I<sub>o<\/sub> is the maximum input current. The nominal value for this resistance is about 75\u03a9. Its calculation is lengthy [20]. This impedance must be matched to the electromagnetic wave impedance. The electromagnetic wave impedance in <em>free<\/em> space is calculated from equation (31), [21];<\/p>\n<p>R<sub>o<\/sub> = \u221a \u03bc <sub>o <\/sub>\/ \u03b5 <sub>o\u00a0 <\/sub>(31)<\/p>\n<p>\u03bc<sub> o<\/sub> permeability of free space = 1.257 x 10<sup>&#8211;<\/sup>8 H\/cm<\/p>\n<p>\u03b5 <sub>0<\/sub> permittivity of free space = 8.854 x 10<sup>-14<\/sup> F\/cm<\/p>\n<p>Using these values in equation (23), we obtain;<\/p>\n<p>Ro \u2248 377 \u03a9 (32)<\/p>\n<p>Thus, the mentioned dipole antenna will not be matched to this impedance. The reflection coefficient is calculated from following equation [22];<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?|\\Gamma&amp;space;|=&amp;space;\\frac{R_{r}-R_{o}}{R_{r}+R_{o}}\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;33&amp;space;\\right&amp;space;)\" alt=\"|\\Gamma |= \\frac{R_{r}-R_{o}}{R_{r}+R_{o}}\\, \\, \\, \\, \\, \\left ( 33 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>Using R<sub> r<\/sub> = 75, and R<sub>o<\/sub> = 377, we obtain;<\/p>\n<p>|\u0393| \u2550-66.8 %! (34)<\/p>\n<p>Thus, half-wave dipole will not receive maximum electromagnetic power. On the other hand Folded \u2500 dipole, discussed below, will offer higher impedance, thus providing optimum power.<\/p>\n<p>Half-wave dipoles are used for MW \u2013 H.F. frequency range. Below or above these frequencies their lengths become either too long or too short. They must be installed horizontally to receive horizontally polarized wave. In addition, horizontal dipole antenna shown in Fig 18 should be installed well above the ground to be less sensitive to radiation from the earth&#8217;s surface and ground wave. This is why most transmitting radio stations prefer vertical quarter-wave antennas, which will be discussed later. In addition, dipole antenna installation requires poles and insulations.<\/p>\n<p>2.4.2. Folded \u2013 dipole: Folded dipole usually referred to as Yagi is a paper clip shape radiator shown in Fig. 19 [23]. It is used universally at VHF covering TV channels 2-12. Above this range, we enter UHF region and dipole length becomes too short for practical applications, thus, a different types of antennas are required.<\/p>\n<p><img loading=\"lazy\" width=\"565\" height=\"457\" class=\"wp-image-5772 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0001_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0001_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0001_new-jpg-4.jpeg 565w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0001_new-jpg-4-300x243.jpeg 300w\" sizes=\"(max-width: 565px) 100vw, 565px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 19- A three elements array with folded dipole is used for TV channels 2 &#8211; 12 <\/strong><\/p>\n<p>The radiation input impedance of folded dipole can be determined from equation (27) using I<sub>o<\/sub>\/2 instead of I<sub>o<\/sub> which is used for regular dipole. Thus, the impedance of folded dipole will be four times the impedance of regular dipole, i.e. 300\u03a9. The reflection coefficient using equation (33) will be;<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?|\\Gamma&amp;space;|=&amp;space;\\frac{300-377}{300+377}=&amp;space;0.11\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;35&amp;space;\\right&amp;space;)\" alt=\"|\\Gamma |= \\frac{300-377}{300+377}= 0.11\\, \\, \\, \\, \\, \\left ( 35 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>This remarkable improvement in the reflection coefficient as compared to the regular dipole is due to reshaping the antenna to obtain a matching impedance to that of free space electromagnetic wave impedance of 377\u03a9, thus receiving optimum power. In addition to impedance matching, reshaping the antenna has also a profound effect on its radiation pattern.<\/p>\n<p>2.4.3. Quarter-Wave Monopole: Fig.20. This antenna is used mostly by radio transmitting stations due to its simplicity of installation and shorter length. Its length is quarter wavelength; ground is mirror image making it virtual halfway dipole. Comparing with regular dipole, we can conclude that its input radiation impedance should be half of regular dipole, i.e. 37.5\u03a9. Reflection coefficient will be;<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?|\\Gamma&amp;space;|=&amp;space;\\frac{37.5-377}{37.5+377}=&amp;space;0.81\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;36&amp;space;\\right&amp;space;)\" alt=\"|\\Gamma |= \\frac{37.5-377}{37.5+377}= 0.81\\, \\, \\, \\, \\, \\left ( 36 \\right )\" align=\"absmiddle\" \/><\/p>\n<p><img loading=\"lazy\" width=\"686\" height=\"270\" class=\"wp-image-5773 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0002_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0002_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0002_new-jpg-4.jpeg 686w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0002_new-jpg-4-300x118.jpeg 300w\" sizes=\"(max-width: 686px) 100vw, 686px\" \/><\/p>\n<p style=\"text-align: center;\"><b>Fig. 20 \u2013 Quarter-wave mono-pole antenna<\/b><\/p>\n<p>Thus, a quarter-wave mono-poles are in fact inefficient radiators. One method to increase their efficiencies is to wrap it around as shown. However, this is not an impedance matching; it merely matches its length to the wavelength, \u03bb, since its length becomes extremely long for MW frequencies.<\/p>\n<p>2.4.4. Baluns and Transformers: Baluns are a U-shaped \u03bb\/2 coaxial cables, while transformers are ferrite core devices used especially for antennas matching; coax to twin flat or vice versa Fig. 21, [4].<\/p>\n<p><img loading=\"lazy\" width=\"1001\" height=\"376\" class=\"wp-image-5774\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0003_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0003_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0003_new-jpg-4.jpeg 1001w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0003_new-jpg-4-300x113.jpeg 300w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0003_new-jpg-4-768x288.jpeg 768w\" sizes=\"(max-width: 1001px) 100vw, 1001px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 21 Impedance matching devices (a) ferrite core transformer (b) \u03bb\/2 balun<\/strong><\/p>\n<p>Baluns are used to convert coax cable impedance to twin-flat, thus obtaining a balanced load while transformer is used to convert impedances balance or unbalance. Ferrite core transformers have wider bandwidth over \u03bb\/2 coaxial balun. Depending on the type of the cable, which connects the antenna terminal to the receiver terminal, there are four configurations shown in Fig. 22.<strong> <img loading=\"lazy\" width=\"1203\" height=\"799\" class=\"wp-image-5775\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0004_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0004_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0004_new-jpg-4.jpeg 1203w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0004_new-jpg-4-300x199.jpeg 300w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0004_new-jpg-4-768x510.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0004_new-jpg-4-1024x680.jpeg 1024w\" sizes=\"(max-width: 1203px) 100vw, 1203px\" \/><\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 22 Impedance matching configurations using trans or balun<\/strong><\/p>\n<p>From these configurations, the first two, which uses twin flat conductors, are obsolete due to high cable radiation losses. Configuration (c) is no longer available since almost all TV sets are now built with 75\u03a9 input impedance. Also in modern technology with satellite receiver, the use of transformer after dipole becomes redundant.<\/p>\n<p><strong>2.5. Microwave Antennas: <\/strong>The latest microwave frequency allocation by FCC ranges from 1 GHz to 100 GHz and it is subdivided in to several bands such as L, S, C, X, and Ku bands. Table 4 shows some popular microwave frequency bands and their applications.<\/p>\n<p style=\"text-align: center;\"><strong>Table 4 \u2013 Popular microwave frequency bands<\/strong><\/p>\n<table>\n<tbody>\n<tr>\n<td>Frequency (GHz)<\/td>\n<td>Designation<\/td>\n<td>Application<\/td>\n<\/tr>\n<tr>\n<td>2.45<\/td>\n<td>LS<\/td>\n<td>Microwave oven<\/td>\n<\/tr>\n<tr>\n<td>2.45<\/td>\n<td>C<\/td>\n<td>Wi &#8211; FiWi-Max<\/td>\n<\/tr>\n<tr>\n<td>4\/6<\/td>\n<td>C<\/td>\n<td>Satellite communication<\/p>\n<p>Down link\/uplink<\/td>\n<\/tr>\n<tr>\n<td>10<\/td>\n<td>X<\/td>\n<td>Radar<\/td>\n<\/tr>\n<tr>\n<td>12\/14<\/td>\n<td>Ku<\/td>\n<td>Satellite communication<\/p>\n<p>Down link\/uplink<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>At these frequencies, wavelength becomes too short, about centimeter. For example at 10 GHz, using \u03bb = c \/ f, we obtain 3 cm. Using Quarter-wave antenna, its length will be one fourth of this, or 0.75 cm. The impedance matching of such antennas is not done on conventional methods discussed<\/p>\n<p>so far. Their impedance matching requires special shaping the structure of the media to obtain optimum output power. One such structure is shown in Fig. 23, horn antenna. Horn antennas have their own history, in addition to their impedance matching properties; they possess high gain and wider bandwidth [25]. To determine their reflection coefficient, we need to evaluate the waveguide impedance. The rectangular waveguide impedance can be calculated from the following equation [26];<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?Z_{g}=&amp;space;\\frac{Z_{o}}{\\sqrt{1-(\\lambda&amp;space;_{o}\/2a)^{2}}}\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;37&amp;space;\\right&amp;space;)\" alt=\"Z_{g}= \\frac{Z_{o}}{\\sqrt{1-(\\lambda _{o}\/2a)^{2}}}\\, \\, \\, \\, \\, \\left ( 37 \\right )\" align=\"absmiddle\" \/><\/p>\n<p><img loading=\"lazy\" width=\"860\" height=\"345\" class=\"wp-image-5776\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0005_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0005_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0005_new-jpg-4.jpeg 860w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0005_new-jpg-4-300x120.jpeg 300w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0005_new-jpg-4-768x308.jpeg 768w\" sizes=\"(max-width: 860px) 100vw, 860px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 23 Horn antenna with quarter-wave radiator<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>(a) none &#8211; flared waveguide (b) two &#8211; directional-flared waveguide<\/strong><\/p>\n<p>Z <sub>g<\/sub> waveguide impedance<\/p>\n<p>Z<sub> o<\/sub> is the free space E\/M wave impedance<\/p>\n<p>\u03bb<sub> o<\/sub> is free space wavelength<\/p>\n<p>a is the wider flange dimension<\/p>\n<p>For X band, (f = 10 GHz), \u03bb<sub>o<\/sub> is found to be 3 cm. The flange dimension a, is given in the Waveguide handbook, 2.5 cm. Inserting these values in to equation (37) with Z <sub>o<\/sub> =377, we obtain 471\u03a9. This value has been experimentally verified in our lab [27]. The reflection coefficient calculated to be;<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?|\\Gamma&amp;space;|=&amp;space;\\frac{Z_{g}-Z_{o}}{Z_{g}+Z_{o}}=&amp;space;\\frac{471-377}{471+377}=&amp;space;0.11\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;38&amp;space;\\right&amp;space;)\" alt=\"|\\Gamma |= \\frac{Z_{g}-Z_{o}}{Z_{g}+Z_{o}}= \\frac{471-377}{471+377}= 0.11\\, \\, \\, \\, \\left ( 38 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>This remarkable reduction in reflection coefficient, as compared to other radiators, is due to reshaping of the antenna as mentioned earlier. In addition to reshaping the waveguide, other impedance matching methods such as mechanical devices using screw tuners shown in Fig. 24 are used in waveguides [28]. The screw tuners, basically, act likes an inductor and a capacitor. The waveguide outputs, however, must be connected ia a microwave detector to a monitoring device such as a power meter or to a scope to observe the output while tuning the screw.<\/p>\n<p><img loading=\"lazy\" width=\"520\" height=\"402\" class=\"wp-image-5777 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/stub-tunet-33.jpeg\" alt=\"stub tunet\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/stub-tunet-33.jpeg 520w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/stub-tunet-33-300x232.jpeg 300w\" sizes=\"(max-width: 520px) 100vw, 520px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 24 a waveguide tuning stub<\/strong><\/p>\n<p><strong>2.6. Optical Lenses: <\/strong>Optical media and T-lines have an intrinsic connection since they both carry electromagnetic wave. For example, the impedance properties of fibers can be extracted from T \u2013 lines by replacing, Z, with n, the index of refraction defined by;<\/p>\n<p>n = c\/v\u00a0 \u00a0 \u00a0 (39)<\/p>\n<p>Where c\/v is the velocity of wave in the vacuum and in the media respectively. Wave velocity, v, in the media is always less than c, therefore, n, is always larger than one. Some representative values of n are given in table 5 [29].<\/p>\n<p style=\"text-align: center;\"><strong>Table 5 \u2013 Index of refraction for some materials used in fibers<\/strong><\/p>\n<table>\n<tbody>\n<tr>\n<td>Material<\/td>\n<td>Index of Refraction(n)<\/td>\n<\/tr>\n<tr>\n<td>Air<\/td>\n<td>1<\/td>\n<\/tr>\n<tr>\n<td>Silica (glass)<\/td>\n<td>1.5<\/td>\n<\/tr>\n<tr>\n<td>Plastic<\/td>\n<td>1.49<\/td>\n<\/tr>\n<tr>\n<td>Water<\/td>\n<td>1.33<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>One important property of optical lenses is their reflection coefficient. This can be extracted and optimized, from the equation of a loaded T- line shown in Fig. 25 as follows;<\/p>\n<p><img loading=\"lazy\" width=\"981\" height=\"242\" class=\"wp-image-5778\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0006_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0006_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0006_new-jpg-4.jpeg 981w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0006_new-jpg-4-300x74.jpeg 300w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0006_new-jpg-4-768x189.jpeg 768w\" sizes=\"(max-width: 981px) 100vw, 981px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 25 Analogy of T- line to optical lens<\/strong><\/p>\n<p>The input impedance of this line is given in equation (17), repeated here is;<\/p>\n<p><img loading=\"lazy\" width=\"285\" height=\"44\" class=\"wp-image-5779\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_inz_c-fracz_ljz_ctan2-pi-l-lambda-64.gif\" alt=\"Z_{in}=Z_{c}\\frac{Z_{L}+JZ_{c}tan(2\\pi l\/\\lambda )}{Z_{c}+JZ_{L}tan(2\\pi l\/\\lambda )}\\: \\: \\: \\: \\: \\: (17)\" \/><\/p>\n<p>For a quarter-wave length, l = \u03bb\/4, after evaluating the limit, this equation reduces to;<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?Z_{in}=&amp;space;\\frac{Z_{c}^{2}}{Z_{L}}\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;21&amp;space;\\right&amp;space;)\" alt=\"Z_{in}= \\frac{Z_{c}^{2}}{Z_{L}}\\, \\, \\, \\, \\, \\left ( 21 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>Incidentally, this is the same equation (17-1). If we now terminate this impedance with a source having impedance Z<sub>s<\/sub>, as shown in the above figure, the reflection coefficient will be;<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?|\\Gamma&amp;space;|=&amp;space;\\frac{Z_{in}-Z_{s}}{Z_{in}+Z_{s}}\\:&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;40&amp;space;\\right&amp;space;)\" alt=\"|\\Gamma |= \\frac{Z_{in}-Z_{s}}{Z_{in}+Z_{s}}\\: \\, \\, \\, \\, \\left ( 40 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>Inserting Z<sub>in<\/sub> from equation (21) in to equation (40), we obtain;<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?\\Gamma&amp;space;=&amp;space;\\frac{Z_{c}^{2}-Z_{s}Z_{L}}{Z_{c}^{2}+Z_{s}Z_{L}}\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;41&amp;space;\\right&amp;space;)\" alt=\"\\Gamma = \\frac{Z_{c}^{2}-Z_{s}Z_{L}}{Z_{c}^{2}+Z_{s}Z_{L}}\\, \\, \\, \\, \\, \\left ( 41 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>If we now replace followings [30]:<\/p>\n<p>Z<sub>L <\/sub>\u2192 n3<\/p>\n<p>Z<sub>c<\/sub> \u2192 n2 (42)<\/p>\n<p>Z<sub>s<\/sub> \u2192n1<\/p>\n<p>Equation (41) transforms to:<\/p>\n<p><img src=\"http:\/\/latex.codecogs.com\/gif.latex?|\\Gamma&amp;space;|=&amp;space;\\frac{n_{2}^{2}-n_{1}n_{3}}{n_{2}^{2}+n_{1}n_{3}}\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\,&amp;space;\\left&amp;space;(&amp;space;43&amp;space;\\right&amp;space;)\" alt=\"|\\Gamma |= \\frac{n_{2}^{2}-n_{1}n_{3}}{n_{2}^{2}+n_{1}n_{3}}\\, \\, \\, \\, \\, \\left ( 43 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>and for optimum transmission, we require;<\/p>\n<p>|\u0393| = 0, or<\/p>\n<p>n2 = \u221a n1. n3\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (44)<\/p>\n<p>This is exactly analogs to equation (23) of T \u2013 lines. Optical technology apply thin layer of antireflection (AR) coating to reduce the reflection, user should take care not to remove this coating by cleaning the lens quite often unless it is done with special cloth.<\/p>\n<p><strong>2.7. Acoustical Instruments<\/strong> \u2013 Wind instruments also use the method of re-shaping their out puts opening to match the instruments acoustical output impedance to the impedance of air, whatever it may be! Fig 26 shows two such instruments. Trumpets have narrow opening, their output acoustical impedances does not much to the impedance of the air. This is noticeable from the high frequency sound due to reflection from the air creating standing wave, while horn has very low frequency sound due to travelling wave.<\/p>\n<p style=\"padding-left: 80px;\"><img loading=\"lazy\" width=\"250\" height=\"83\" class=\"wp-image-5780\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-250px-trumpet_11-jpg-33.jpeg\" alt=\"C:\\Users\\mm\\Desktop\\250px-Trumpet_1[1].jpg\" \/><img loading=\"lazy\" width=\"250\" height=\"178\" class=\"wp-image-5781\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-250px-french_horn_front1-png-33.png\" alt=\"C:\\Users\\mm\\Desktop\\250px-French_horn_front[1].png\" \/><\/p>\n<p>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (a)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (b)<\/p>\n<p style=\"text-align: center;\"><strong>Fig. 26 Wind instruments flared for impedance conversion (a) Trumpet (b) horn <\/strong><\/p>\n<p><strong>Appendices<\/strong><\/p>\n<p><strong>1. Communication Cables Losses Per 100 Ft.<\/strong><\/p>\n<p><img loading=\"lazy\" width=\"628\" height=\"430\" class=\"wp-image-5782 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/100ft-33.jpeg\" alt=\"100FT\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/100ft-33.jpeg 628w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/100ft-33-300x205.jpeg 300w\" sizes=\"(max-width: 628px) 100vw, 628px\" \/><\/p>\n<p><img loading=\"lazy\" width=\"1430\" height=\"1147\" class=\"wp-image-5783\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new_0001-jpg-2.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_NEW_0001.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new_0001-jpg-2.jpeg 1430w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new_0001-jpg-2-300x241.jpeg 300w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new_0001-jpg-2-768x616.jpeg 768w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_new_0001-jpg-2-1024x821.jpeg 1024w\" sizes=\"(max-width: 1430px) 100vw, 1430px\" \/><\/p>\n<p><strong>References<\/strong><\/p>\n<p>[1]. William H. Timbie, Vannevar Bush, George B. Hoadley,&#8221; Principles of Electrical Engineering&#8221; 4<sup>th<\/sup> ed, John Wiley &amp; Sons, Inc., New York 1951, pages392- 403.<\/p>\n<p>[2]. George F. Corcoran, Henry R. Reed, &#8220;Introductory Electrical Engineering,&#8221; John Wiley &amp; Sons, Inc., 1957, pages 297-303.<\/p>\n<p>[3]. Edward C. Jordan, Keith G. Balmain, &#8220;Electromagnetic Waves and Radiation System,&#8221; Prentice-Hall, Inc., 1968, chapter 7.<\/p>\n<p>[4]. Electronic Design, Oct.3, 1994.<\/p>\n<p>[5]. H. Javan, &#8220;Noise Measure for Optimum Broadband Design,&#8221; IEE Proceedings-G, Circuits, Devices and Systems, Vol. 138, No. 1, Feb. 1991.<\/p>\n<p>[6]. Constantine A. Balanis, &#8220;Antenna Theory, Analysis and Design,&#8221; John Wiley &amp; Sons, Inc., 1982, pages 466-483.<\/p>\n<p>[7]. P. H. Smith, &#8220;An Improved Transmission Line Calculator,&#8221; http:\/\/www.maximintegrated.com\/en\/app-notes\/index.mvp\/id\/742Electronics, 17, 130, (Jan., 1944; also 12, 29 (Jan., 1939).<\/p>\n<p>[8]. Selected references for Smith Chart with no or limited adds:http:\/\/www.files32.com\/Smith-Chart.asp<\/p>\n<p><a href=\"https:\/\/search.yahoo.com\/search;_ylt=Am2SkeQCUPRBCLSk0ZHxgUGbvZx4?fr=yfp-t-474-s&amp;toggle=1&amp;fp=1&amp;cop=mss&amp;ei=UTF-8&amp;p=smith%20chart%20impedance%20matching\">https:\/\/search.yahoo.com\/search;_ylt=Am2SkeQCUPRBCLSk0ZHxgUGbvZx4?fr=yfp-t-474-s&amp;toggle=1&amp;fp=1&amp;cop=mss&amp;ei=UTF-8&amp;p=smith%20chart%20impedance%20matching<\/a><\/p>\n<p><a href=\"http:\/\/www.maximintegrated.com\/en\/app-notes\/index.mvp\/id\/742\">http:\/\/www.maximintegrated.com\/en\/app-notes\/index.mvp\/id\/742<\/a><\/p>\n<p><a href=\"http:\/\/www.qsl.net\/va3iul\/Smith%20Chart\/smith.html\"><strong>http:\/\/www.qsl.net\/va3iul\/Smith%20Chart\/smith.html<\/strong><\/a><\/p>\n<p>[9]. Edward C. Jordan, &#8220;Electromagnetic Waves and Radiation Systems,&#8221; Prentice-Hall, Inc., 1968, pages 232-140.<\/p>\n<p>[10]. H. Javan, D. Wirth, &#8220;Senior Thesis, Impedance Program,&#8221; Tech 4944, Dept. of Engineering Tech, Univ. of Memphis, fall 1999.<\/p>\n<p>[11]. <a href=\"http:\/\/en.wikipedia.org\/wiki\/Smith_chart\">http:\/\/en.wikipedia.org\/wiki\/Smith_chart<\/a><\/p>\n<p>[12]. Phillip H. Smith, &#8220;An Improved Transmission Line Calculator,&#8221; Analog Instrument Co. Box 950, New Providence, N.J. 07974.<\/p>\n<p>[13]. Tektronix, TDR 1503C, Metallic Cable Tester.<\/p>\n<p>[14]. Dan Moline, &#8220;Motorola&#8217;s Impedance Matching Program, (1),&#8221; 6 April 1992, Version 1.0.<\/p>\n<p>[15]. Richard F. Shea, Editor &#8220;Transistor Circuit Engineering,&#8221; John Wiley &amp; Sons, Inc., New York, 1957, page 244-250.<\/p>\n<p>[16]. Jacob Millman, Arvin Grabel, &#8220;Microelectronics,&#8221; 2<sup>nd<\/sup> ed. McGraw-Hill Book Company, 1987, page 419-422.<\/p>\n<p>[17]. Ibid, pages 803-806.<\/p>\n<p>[18]. <a href=\"http:\/\/en.wikipedia.org\/wiki\/Guglielmo_Marconi\">http:\/\/en.wikipedia.org\/wiki\/Guglielmo_Marconi<\/a>.<\/p>\n<p>[19]. L.Pazin, N. Telzhensky and Y. Leviatan, &#8220;Multiband Flat-Plate Inverted-F Antenna for Wi-Fi\/WiMax operation,&#8221; IEEE Antennas and Wireless Propagation Letters, 7: 197-200, 2008.<\/p>\n<p>[20]. Constantine A. Balanis, &#8220;Antenna Theory, Analysis and Design,&#8221; John Wiley &amp; Sons, Inc., 1982, pages 162-164.<\/p>\n<p>[21]. John D. Kraus, Keith R. Carver, &#8220;Electromagnetics,&#8221; 2<sup>nd<\/sup> ed., McGraw-Hill, Inc., 1973, pages 378-381.<\/p>\n<p>[22]. Edward C. Jordan, Keith G. Balmain, &#8220;Electromagnetic Waves and Radiation System,&#8221; Prentice-Hall, Inc., 1968, pages 215-217.<\/p>\n<p>[23]. Shintaro Uda, Hidetsugu Yagi, Tohoku Imperial University, 1926<\/p>\n<p>[24]. Constantine A. Balanis, &#8220;Antenna Theory, Analysis and Design,&#8221; John Wiley &amp; Sons, Inc., 1982, pages 480-483.<\/p>\n<p>[25]. Constantine A. Balanis, &#8220;Antenna Theory, Analysis and Design,&#8221; John Wiley &amp; Sons, Inc., 1982, pages 651, 682-692.<\/p>\n<p>[26]. T. Koryu Ishii, &#8220;Microwave Engineering,&#8221; 2<sup>nd<\/sup> ed., Harcourt Brace Jovanovich, Publisher, 1989, pages 186-189.<\/p>\n<p>[27]. H. Javan, EETH 7821, &#8220;Advanced Microwave Technology,&#8221; Project No.6, Antenna Measurement, University of Memphis, Dept. of Engineering Tech, fall 2011.<\/p>\n<p>[28]. Hewlett-Packard Company.<\/p>\n<p>[29]. Joseph C. Palais, &#8220;Fiber Optic Communications,&#8221; 4<sup>th<\/sup> ed., Prentice-Hall, Inc. 1998, pages 33-38, pages 71-72.<\/p>\n<p>[30]. H. Javan, EETH 7841, &#8220;Fiber Optics in Communication,&#8221; Dept. of Engineering Tech., University of Memphis, Memphis, TN 38152, fall 2000.<\/p>\n<p><strong>Problems<\/strong><\/p>\n<p><strong>1. General Concept<\/strong><\/p>\n<p>1. A 20 Watts two channels stereo system each with 8\u03a9 out pout impedance is to be connected to 4 speakers as shown in Fig. 36. Determine each speaker&#8217;s impedance and power rating.<\/p>\n<p><img loading=\"lazy\" width=\"585\" height=\"242\" class=\"wp-image-5784 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0008_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0008_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0008_new-jpg-4.jpeg 585w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0008_new-jpg-4-300x124.jpeg 300w\" sizes=\"(max-width: 585px) 100vw, 585px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 27 Stereo system for problem 1<\/strong><\/p>\n<p>2. A reactive source with impedance Zs = Rs + J Xs is to be connected to a load Z<sub>L<\/sub> as shown in Fig. 38. Determine the elements of Z<sub>L <\/sub>to receive optimum power.\u00a0Hint: Follow the steps presented in <strong>Case 1<\/strong> for resistive source.<\/p>\n<p><img loading=\"lazy\" width=\"301\" height=\"102\" class=\"wp-image-5785 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-385.png\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-385.png 301w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/word-image-385-300x102.png 300w\" sizes=\"(max-width: 301px) 100vw, 301px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 28 Circuit for problem 2<\/strong><\/p>\n<p><strong>2. Methodologies<\/strong><\/p>\n<p><strong>2.1. Transformer Method<\/strong><\/p>\n<p>3. A 24 V, 10 Watts audio push-pull amplifier having an output impedance R<sub>o<\/sub>=16\u03a9 is to deliver maximum power to two speakers each 8\u03a9 as shown in Fig. 39. Determine the ratios of N1\/N2, N1\/N3, and the power delivered to each speaker.<\/p>\n<p><img loading=\"lazy\" width=\"799\" height=\"370\" class=\"wp-image-5786 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0009_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0009_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0009_new-jpg-4.jpeg 799w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0009_new-jpg-4-300x139.jpeg 300w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0009_new-jpg-4-768x356.jpeg 768w\" sizes=\"(max-width: 799px) 100vw, 799px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 29 Circuit for problem 3<\/strong><\/p>\n<p><strong>2.2. Transmission Line Technology<\/strong><\/p>\n<p>4. Given general T- line equation (17), determine Z<sub>in<\/sub> for the following two cases, thus verifying tabulated representation in table (3).<\/p>\n<p>Short terminated, l=\u03bb\/4, l=\u03bb\/2<\/p>\n<p><img loading=\"lazy\" width=\"289\" height=\"44\" class=\"wp-image-5787\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_in-z_c-fracz_ljz_ctan2pl-lambda-67.gif\" alt=\"Z_{in}= Z_{c}\\frac{Z_{L}+JZ_{c}tan(2Pl\/\\lambda )}{Z_{c}+JZ_{L}tan(2Pl\/\\lambda)}\\: \\: \\: \\: \\: \\: (17)\" \/><\/p>\n<p>5. Consider above equation, for what value of L, will the input impedance, Z<sub>in<\/sub> be equal to Z<sub>L<\/sub>?<\/p>\n<p>This case is of practical importance for impedance matching.<\/p>\n<p>6. Consider equation (17) above with a reactive load, Z<sub>L<\/sub>. It is shown graphically in example 1, that somewhere along the line, Z<sub>in<\/sub> becomes pure resistive, i.e. Z<sub>in<\/sub> = R<sub>in<\/sub>. Determine the required length of the line.\u00a0Hint: separate real and imaginary parts.<\/p>\n<p>7. Consider equation (23) quarter-wavelength for impedance matching. Since Z<sub>c <\/sub>is generally resistive, it is necessary that both Z<sub>s <\/sub>and Z<sub>L<\/sub> to be resistive. There is one exception under which Z<sub>c <\/sub>will still be resistive with Z<sub>s<\/sub>, and Z<sub>L<\/sub> being reactive. Determine these impedances.<\/p>\n<p>Z <sub>c<\/sub> = \u221a Z<sub>s<\/sub> Z<sub>L<\/sub> (23)<\/p>\n<p>8. Given ZL = 31.25 + J 10, Zs=50, use shunt stub matching, determine d1, d2, and X. using Smith chart. Blank Smith chart is provided at the end.<\/p>\n<p><strong>2.3. Solid State Electronics \u2013 Impedance conversion<\/strong><\/p>\n<p>9. An emitter follower uses transformer to feed the 8\u03a9 speaker as shown in Fig. 40. Determine the transformer turn ratio to match the speaker to the source impedance R<sub>s <\/sub>of 1k\u03a9. The current gain of the transistor, h<sub>fe<\/sub> is 200.<\/p>\n<p><img loading=\"lazy\" width=\"653\" height=\"477\" class=\"wp-image-5788 aligncenter\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0010_new-jpg-4.jpeg\" alt=\"C:\\Users\\hank\\Desktop\\IMG_0010_NEW.jpg\" srcset=\"https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0010_new-jpg-4.jpeg 653w, https:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-hank-desktop-img_0010_new-jpg-4-300x219.jpeg 300w\" sizes=\"(max-width: 653px) 100vw, 653px\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Fig. 30 Circuit for problem 9<\/strong><\/p>\n<p><strong>2.4. Antenna Impedance Matching<\/strong><\/p>\n<p>10. Design a half-wave dipole and quarter-wave mono-pole to receive a shortwave station at f= 950 MHz.<\/p>\n<p>11. A Balun is used to match the folded dipole to RG 59. Determine its length for channel 12, f=112 MHz.<\/p>\n<p><strong>2.5. Microwave Antennas<\/strong><\/p>\n<p>12. Determine wave guide impedance given by equation (37) for X band, thus verifying the value cited in the section. Why wave impedance is larger inside the waveguide than the free space wave impedance? Use Z<sub>o<\/sub> \u2550377\u03a9, f\u255010 GHz, a\u25502.5 cm.<\/p>\n<p><img loading=\"lazy\" width=\"211\" height=\"45\" class=\"wp-image-5789\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/z_g-fracz_o-sqrt1-lambda-_o-2a2-33.gif\" alt=\"Z_{g}=\\frac{Z_{o}}{\\sqrt{1-(\\lambda _{o}\/2a)^{2}}}\\, \\, \\, \\, \\, \\, (37)\" \/><\/p>\n<p>13. In shaping the waveguide in to horn, which parameter is affected; directivity (gain) or the impedance of the waveguide?<\/p>\n<p><img class=\"wp-image-5790\" src=\"http:\/\/javan.courses\/wp-content\/uploads\/2019\/05\/c-users-mm-desktop-2015_01_31-img-tif-33.tiff\" alt=\"C:\\Users\\mm\\Desktop\\2015_01_31\\IMG.tif\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>1. General Concept 1.1. Case 1. Low Frequency Analysis 1.1.1. Mathematical Method 1.1.2. Graphical Method 1.2. Case 2. High Frequency Signals 2. Methodologies 2.1. Transformer Method 2.2. Transmission Line Technology 2.2.1. Short Circuited T-line 2.2.2. Open Circuited T-line 2.2.3. Quarter-wave Transformer 2.2.4. Pure Input Resistance 2.2.5. Stub Matching 2.3. Solid State Electronics \u2013 Impedance Conversion &#8230; <a title=\"SERIES 1- IMPEDANCE CONVERSION THEORIES AND TECHNIQUES\" class=\"read-more\" href=\"https:\/\/javan.courses\/?page_id=5725\" aria-label=\"More on SERIES 1- IMPEDANCE CONVERSION THEORIES AND TECHNIQUES\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":[],"_links":{"self":[{"href":"https:\/\/javan.courses\/index.php?rest_route=\/wp\/v2\/pages\/5725"}],"collection":[{"href":"https:\/\/javan.courses\/index.php?rest_route=\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/javan.courses\/index.php?rest_route=\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/javan.courses\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/javan.courses\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=5725"}],"version-history":[{"count":52,"href":"https:\/\/javan.courses\/index.php?rest_route=\/wp\/v2\/pages\/5725\/revisions"}],"predecessor-version":[{"id":13334,"href":"https:\/\/javan.courses\/index.php?rest_route=\/wp\/v2\/pages\/5725\/revisions\/13334"}],"wp:attachment":[{"href":"https:\/\/javan.courses\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=5725"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}